I found this page on the internet showing motors for stairlifts by Parvalux along with their power rating in watts yesterday. A Watt (W) is equal to Voltage (V) times current( I ) and written in formula form : W=VI or I = W/V. The stairlift motors Parvalux shows in its sales brochure (https://www.parvalux.com/applications/trusted-in-healthcare/stairlifts) have high side power ratings (W) from 345 to 583 watts. Using the I = W/V and using 24 volts as the lift voltage, the max current (amperage) for these motors should run from 14.3 amps to 24.3 amps.
Assuming the electrical designers built in a 50 % overload/safety factor in design, the amperage draw would be from about 7 amps to 12 amps. They seem to be reasonable numbers to me. Knowing the voltage and amperage rating of the fuse of the Acorn lift would allow one to get closer to the actual running amps. By the way, one fellow on the internet claims to have built a circuit using a 12 v 7 amp battery that operated at 100 amps for 1 minute.
One other note: a Lemac 24 volt motor reportedly from an Acorn stairlift on the internet stated the motor was 375 watts at 53 rpm. With that info I’d think the Acorn lifts may run somewhat below 7 amps and have a fuse rated about 10 amps or more. As I noted in a previous post, I’d expect the starting amps to be higher ( until the motor gets to its normal running speed) so the higher fuse rating would account for that..
Slowly but surely zeroing in on getting to understand how the lift motor and batteries work.
Comments appreciated.
